(x+3)(2x^2-x-3)=0

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Solution for (x+3)(2x^2-x-3)=0 equation: 


Simplifying
(x + 3)(2x2 + -1x + -3) = 0

Reorder the terms:
(3 + x)(2x2 + -1x + -3) = 0

Reorder the terms:
(3 + x)(-3 + -1x + 2x2) = 0

Multiply (3 + x) * (-3 + -1x + 2x2)
(3(-3 + -1x + 2x2) + x(-3 + -1x + 2x2)) = 0
((-3 * 3 + -1x * 3 + 2x2 * 3) + x(-3 + -1x + 2x2)) = 0
((-9 + -3x + 6x2) + x(-3 + -1x + 2x2)) = 0
(-9 + -3x + 6x2 + (-3 * x + -1x * x + 2x2 * x)) = 0
(-9 + -3x + 6x2 + (-3x + -1x2 + 2x3)) = 0

Reorder the terms:
(-9 + -3x + -3x + 6x2 + -1x2 + 2x3) = 0

Combine like terms: -3x + -3x = -6x
(-9 + -6x + 6x2 + -1x2 + 2x3) = 0

Combine like terms: 6x2 + -1x2 = 5x2
(-9 + -6x + 5x2 + 2x3) = 0

Solving
-9 + -6x + 5x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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